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Object Oriented Programming By Mam Sidra Malik

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Old 08-09-2008, 10:39 PM   #1
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Default Fraction Calculator with 4 functions in c++ [ex12 of ch#5] Robert Lafore

Fraction Calculator with 4 functions in c++ [ex12 of ch#5]


It adds only fractions like 2/3+4/3 (requirement is question).

Program ki Samajh aaye tu mujhe bhi samjha daina!
Ab tu mujhe khud ko hi samjh nai aa rahi

Exectable is also attached for convenience .

#include <iostream> using namespace std; struct fraction { int numinator,denominator; }; fraction functadd(fraction a,fraction b) { fraction ans; ans.numinator=(a.numinator*b.denominator)+(b.numinator*a.denominator); ans.denominator=a.denominator*b.denominator; return ans; } fraction functsubtr(fraction a,fraction b) { fraction ans; ans.numinator=(a.numinator*b.denominator)-(b.numinator*a.denominator); ans.denominator=a.denominator*b.denominator; return ans; } fraction functmulti(fraction a,fraction b) { fraction ans; ans.numinator=a.numinator*b.numinator; ans.denominator=a.denominator*b.denominator; return ans; } fraction functdivide(fraction a,fraction b) { fraction ans; ans.numinator=a.numinator*b.denominator; ans.denominator=a.denominator*b.numinator; return ans; } void main() { fraction number[2]; char c; char oprtr; fraction result; for(int n=1;n!=0;) { int showans=1; cout<<"\nEnter Values in this form 2/3+4/3 :"; cin>>number[0].numinator>>c>>number[0].denominator>>oprtr>>number[1].numinator>>c>>number[1].denominator; if(oprtr=='+') { result=functadd(number[0],number[1]); n=0; } else if(oprtr=='-') { result=functsubtr(number[0],number[1]); n=0; } else if(oprtr=='*') { result=functmulti(number[0],number[1]); n=0; } else if(oprtr=='/') { result=functdivide(number[0],number[1]); n=0; } else { cout<<"You have used an invalid Operator, Please use any one of following operators\n+ , - , *, /\n\n"; n=1; showans=0; } if (showans==1) { cout<<"Answer = "<<result.numinator<<"/"<<result.denominator; } cout<<"\n\nContinue? y/n"; char var; cin>>var; if(var=='y') n=1; else if(var=='n') { n=0; } } }
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Old 09-09-2008, 06:06 AM   #2


 
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Default Re: Fraction Calculator with 4 functions in c++ [ex12 of ch#5]

Thank you bhai...
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Old 10-09-2008, 12:13 AM   #3
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Default Re: Fraction Calculator with 4 functions in c++ [ex12 of ch#5]

yar is main to - * or / waly ni han pleas tell me understand me
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Old 10-09-2008, 12:20 AM   #4
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Default Re: Fraction Calculator with 4 functions in c++ [ex12 of ch#5]

Sab kucch hay yar,

There are separate functions for subtraction, multiplication & division ...

We've just called that functions, and used if statement to recognize that to which function we've to call...

We can also use switches instead of if statement ..
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Old 18-09-2008, 04:59 AM   #5
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Default Re: Fraction Calculator with 4 functions in c++ [ex12 of ch#5] Robert Lafore

Fraction Calculator with Proper LCM Function
#include <iostream> using namespace std; struct fraction { int numerator,denominator; }; fraction functadd(fraction a,fraction b); fraction functsubtr(fraction a,fraction b); fraction functmulti(fraction a,fraction b); fraction functdivide(fraction a,fraction b); int lcm(int val1, int val2); void main() { fraction number[2]; char c; char oprtr; fraction result; for(int n=1;n!=0;) { int showans=1; cout<<"\nEnter Values in this form 2/3+4/3 :"; cin>>number[0].numerator>>c>>number[0].denominator>>oprtr>>number[1].numerator>>c>>number[1].denominator; switch (oprtr) { case '+': result=functadd(number[0],number[1]); n=0; break; case '-': result=functsubtr(number[0],number[1]); n=0; break; case '*': result=functmulti(number[0],number[1]); n=0; break; case '/': result=functdivide(number[0],number[1]); n=0; break; default: cout<<"You have used an invalid Operator, Please use any one of following operators\n+ , - , *, /\n\n"; n=1; showans=0; break; } if (showans==1) { cout<<"Answer = "<<result.numerator<<"/"<<result.denominator; } cout<<"\n\nContinue? y/n : "; char var; cin>>var; if(var=='y') n=1; else if(var=='n') { n=0; } } } /*----------------------------------------------------------------- Functions are Given Below ------------------------------------------------------------------*/ fraction functadd(fraction a,fraction b) { fraction ans; ans.denominator=lcm(a.denominator,b.denominator); ans.numerator=((ans.denominator/a.denominator)*a.numerator)+(ans.denominator/b.denominator)*b.numerator; return ans; } fraction functsubtr(fraction a,fraction b) { fraction ans; ans.denominator=lcm(a.denominator,b.denominator); ans.numerator=((ans.denominator/a.denominator)*a.numerator)-(ans.denominator/b.denominator)*b.numerator; return ans; } fraction functmulti(fraction a,fraction b) { fraction ans; ans.numerator=a.numerator*b.numerator; ans.denominator=a.denominator*b.denominator; return ans; } fraction functdivide(fraction a,fraction b) { fraction ans; ans.numerator=a.numerator*b.denominator; ans.denominator=a.denominator*b.numerator; return ans; } /*----------------------------------- Function for LCM Starts Here -------------------------------------*/ int lcm(int val1,int val2) { int lcm,check,big; check=65536; //Any Bigger Value greater than big if(val1>val2) big=val1; else if(val1<val2) big=val2; else big=val1; for(;big<=check;big++) { if(big%val1==0 && big%val2==0) { check=0; lcm=big; } } return lcm; } /*----------------------------------- Function for LCM Ends Here -------------------------------------*/
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Old 07-10-2011, 06:17 PM   #6
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Default Re: Fraction Calculator with 4 functions in c++ [ex12 of ch#5] Robert Lafore

ahem...koi isko classes use krtay hwe bna skta hai??
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Old 07-10-2011, 07:09 PM   #7
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Default Re: Fraction Calculator with 4 functions in c++ [ex12 of ch#5] Robert Lafore

well, just create a new class . something like this...
class calculator { private: public: }
then move all functions to the public part of class ... then in main part create new object from class like this
calculator mycal;
then where all functions are called in the main part of program . call them using
mycall.myfunction();
i think this should work...
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Old 08-10-2011, 10:02 AM   #8
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Default Re: Fraction Calculator with 4 functions in c++ [ex12 of ch#5] Robert Lafore

Quote:
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well, just create a new class . something like this...
class calculator { private: public: }
then move all functions to the public part of class ... then in main part create new object from class like this
calculator mycal;
then where all functions are called in the main part of program . call them using
mycall.myfunction();
i think this should work...

i we have o add constructors, then how should we do it??
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