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Program to convert 2digit octal number into binary number and print it Program to convert 2digit octal number into binary number and print it #include <iostream.h> #include <conio.h> void octobin(int); void main() { clrscr(); int a; cout << "Enter a 2digit octal number : "; cin>>a; octobin(a); getch(); } void octobin(int oct) { long bnum=0; int A[6]; //Each octal digit is converted into 3 bits, 2 octal digits = 6 bits. int a1,a2,quo,rem; a2=oct/10; a1=octa2*10; for(int x=0;x<6;x++) { A[x]=0; } //Storing the remainders of the one's octal digit in the array. for (x=0;x<3;x++) { quo=a1/2; rem=a1%2; A[x]=rem; a1=quo; } //Storing the remainders of the ten's octal digit in the array. for(x=3;x<6;x++) { quo=a2/2; rem=a2%2; A[x]=rem; a2=quo; } //Obtaining the binary number from the remainders. for(x=x1;x>=0;x) { bnum*=10; bnum+=A[x]; } cout << "The binary number for the octal number " << oct << " is " << bnum << "." << endl; } This program takes in a twodigit octal number a as a screen input from the user. It then converts the octal number into a binary number and outputs it using the 'cout' command. Sample Input 13 Sample Output The binary number for the octal number 13 is 1011.
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2digit, binary, convert, number, octal, print, program 
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