Quote:
Originally Posted by Ali Riaz A pilot is flying a helicopter around a large equilateral triangular course, with way-points labelled A, B and C. To fly from point A to point B takes him one hour and twenty minutes. To fly from point B to point C takes him another one hour and twenty minutes. However, to fly from point C back to point A ONLY takes him eighty minutes. Since the pilot maintained a constant speed all the way, how did he achieve this? |
It took the same time to reach back to C.
one hour and twenty minutes = 80 mins.
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wow....gr8 yani tumhara demagh or math thk ha....good
or dekhnay mein bhi thk lagty ho
one of the good and wise guy so far i met...nice to meet you bro